WebExpert Answer 100% (3 ratings) Transcribed image text: 2. Let X be a set; let d be a metric on X. Show that the topology on X induced by R is d is the coarsest topology relative to … WebDefinition 1. A space with metric and measure, or an mm-space, is a triple (X,d,µ), where d is a metric on a set X and µ is a finite Borel measure on the metric space (X,d). It will be convenient to assume throughout that µis a probability measure, that is, normalized to one. Definition 2. The concentration function αX of an mm-space X=
Metrizable space - Wikipedia
WebDec 22, 2024 · Is the trivial topology Hausdorff? The trivial topology is the topology with the least possible number of open sets, namely the empty set and the entire space, since the definition of a topology requires these two sets to be open. In particular, it is not a Hausdorff space. Not being Hausdorff, X is not an order topology, nor is it metrizable. WebJun 14, 2024 · The question is one in Munkres where we are asked to prove the metrizability of RxR in the dictionary order topology. My attempts of defining a metric seem to falter at the end. As for example, I have tried the standard bounded metric, usual metric etc...etc., … on the hiking trail
Math 190: Winter 2024 - University of California, San Diego
Web>Why RxR in the dictionary order topology is metrizable? Because it basically is a disjoint sum of copies of R. Every A_x = {x} x R is homeomorphic to R (sending (x,y) to y), even order isomorphic. And any two A_x are "far apart". We could define a metric on RxR as follows: d (x,y) = 1 if x_1 <> y_1, and otherwise y_2-x_2 . WebFeb 15, 2016 · Here's Prob. 2, Sec. 20 in the book Topology by James R. Munkres, 2nd edition: Show that R × R in the dictionary order topology is metrizable. The dictionary … on the high street jewellery